Question

in boxes a and b, the genotypes are shown for you. you need to determine the phenotypes. in boxes c and d, you must figure out the genotypes yourself first. then, determine the phenotypes.

Explanation:

Step1: Determine Box C's Genotype

To find the genotype of Box C, we cross the row (bE) and column (bE) gametes. The row gamete is \( bE \) (from the left mouse's row: be? Wait, no, the left mouse is Bbee, so its gametes are Be, Be, be, be. The top mouse is BbEe, gametes are BE, Be, bE, be. Wait, Box C is at the intersection of row "be" (from left mouse: be) and column "bE" (from top mouse: bE). So the genotype is \( b \times b \) for the first gene and \( E \times e \) for the second? Wait, no: left mouse's gamete for row "be" is \( be \) (since left mouse is Bbee, gametes are Be, Be, be, be. So row "be" is gamete \( be \)). Top mouse's column "bE" is gamete \( bE \). So combining \( be \) and \( bE \): for the first gene (B/b), \( b \times b = bb \); for the second gene (E/e), \( e \times E = Ee \). So Box C's genotype is \( bbEe \).

Step2: Determine Box D's Genotype

Box D is at the intersection of row "Be" (left mouse's gamete \( Be \)) and column "be" (top mouse's gamete \( be \)). So combining \( Be \) and \( be \): first gene \( B \times b = Bb \); second gene \( e \times e = ee \). So Box D's genotype is \( Bbee \).

(Note: For phenotypes, we need to know the dominance. Assuming B is dominant over b, E is dominant over e. So for Box A: BB Ee → phenotype: dominant for B, dominant for E. Box B: BB ee → dominant for B, recessive for E. Box C: bb Ee → recessive for B, dominant for E. Box D: Bb ee → dominant for B, recessive for E. But the question might just be about genotypes for C and D.)

Answer:

Box C: \( bbEe \); Box D: \( Bbee \)