Question

a box with a mass of 5.0 kg rests on a horizontal table. what is the magnitude of the normal force exerted by the table on the box? (assume g = 9.8 m/s2)
hint: n = w = m x g

Explanation:

Step1: Identify the formula

The normal force \(N\) on a horizontal surface when the object is at rest is equal to the weight \(W\) of the object. The formula for weight is \(W = m\times g\), where \(m\) is the mass and \(g\) is the acceleration due to gravity.

Step2: Substitute the values

Given \(m = 5.0\space kg\) and \(g=9.8\space m/s^{2}\). Substitute these values into the formula \(N = m\times g\).
So, \(N=5.0\times9.8\).

Step3: Calculate the result

\(N = 49\space N\)

Answer:

\(49\space N\)