Question

and 2 blocks north. charica walks 1 block east and 9 blocks north. on the graph, the school is located at the origin. determine the distance between garretts house (point g) and chances house (point c). enter the coordinates of the two given points and then calculate the distance between them. coordinates $(x_1,y_1)$ of point g: $(7,2)$ coordinates $(x_2,y_2)$ of point c $(1,9)$ $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$ $d = \sqrt{( - 6)^2+(7)^2}$ $d =$ the distance between garretts house and chances house is blocks

Explanation:

Step1: Substitute coordinates into formula

Given \(x_1 = 7,y_1 = 2,x_2 = 1,y_2 = 9\).
\(x_2 - x_1=1 - 7=-6\), \(y_2 - y_1=9 - 2 = 7\).
So \(d=\sqrt{(-6)^2+(7)^2}\).

Step2: Calculate squares

\((-6)^2 = 36\), \((7)^2=49\).
Then \(d=\sqrt{36 + 49}\).

Step3: Sum and take square - root

\(36+49 = 85\).
\(d=\sqrt{85}\approx9.22\).

Answer:

The distance between Garrett's house and Chance's house is \(\sqrt{85}\approx9.22\) blocks.