below is a diagram that shows the four forces that are acting on an airplane. the table below the diagram explains what happens when one force is greater than the opposing force that it is paired with. (lift is always paired with weight and thrust is always paired with drag)
simplified aircraft motion
unbalanced forces
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6. an airplane has a weight of 100,000 n and a lift force of 75,000n.
a. what is the combined force (net force) on the airplane?
b. are the forces balanced or unbalanced?
7. an airplane has a thrusting force of 200,000 n and a drag force of 23,000 n.
a. what is the combined force (net force) on the airplane?
b. are the forces balanced or unbalanced?
circle the best answer:
8. the forces shown above are pushing / pulling forces.
9. the forces shown above are working together / opposite forces.
10. the forces are equal / not equal.
11. the forces do / do not balance each other.
12. the resultant force is 1000 n to the right / 1000 n to the left / zero.
13. there is / is no motion.

Question

Accepted Answer

# 6.
## a.
# Explanation:
## Step1: Determine the direction of forces
Lift acts upward and weight acts downward. Let's take upward as positive and downward as negative.
## Step2: Calculate the net force
Net force $F_{net}=F_{lift}-F_{weight}$. Given $F_{lift} = 75000N$ and $F_{weight}=100000N$. So $F_{net}=75000 - 100000=- 25000N$ (the negative sign indicates the direction is downward)

# Answer:
The combined force (net force) on the airplane is $25000N$ downward.

## b.
# Brief Explanations:
Since $F_{lift}
eq F_{weight}$ ( $75000N
eq100000N$ ), according to the concept of balanced forces (where for a particular pair of forces,  equal - magnitude and opposite - direction forces result in a net force of zero for that pair).

# Answer:
The forces are unbalanced.

# 7.
## a.
# Explanation:
## Step1: Determine the direction of forces
Thrust acts forward (let's assume positive direction) and drag acts backward (negative direction)
## Step2: Calculate the net force
Net force $F_{net}=F_{thrust}-F_{drag}$. Given $F_{thrust} = 200000N$ and $F_{drag}=23000N$. So $F_{net}=200000 - 23000 = 177000N$ (direction is forward)

# Answer:
The combined force (net force) on the airplane is $177000N$ forward.

## b.
# Brief Explanations:
Since $F_{thrust}
eq F_{drag}$ ($200000N
eq23000N$),  according to the definition of balanced forces (forces in a pair must be equal in magnitude and opposite in direction for the pair to be balanced).

# Answer:
The forces are unbalanced.

# 8.
# Brief Explanations:
Pulling forces are forces that act in a direction towards the source of the force. In the context of the diagram (assuming the people are pulling the rope), it is a pulling force.

# Answer:
PULLING

# 9.
# Brief Explanations:
Opposite forces are forces that act in opposite directions. Here, the two people are pulling the rope in opposite directions.

# Answer:
OPPOSITE

# 10.
# Brief Explanations:
Both forces are $1000N$, so they have the same magnitude.

# Answer:
EQUAL

# 11.
# Brief Explanations:
Balanced forces for a pair mean $F_1=-F_2$ (equal magnitude and opposite direction). Here, the two forces are equal in magnitude ($1000N$) and opposite in direction.

# Answer:
DO

# 12.
# Explanation:
## Step1: Calculate the resultant force
Let $F_1 = 1000N$ (left - direction, assume negative) and $F_2=1000N$ (right - direction, assume positive). Resultant force $F_{res}=F_1 + F_2=-1000 + 1000=0N$

# Answer:
ZERO

# 13.
# Brief Explanations:
According to Newton's first law, when the net force ($F_{net}=0$) on an object,  the object remains in its state of rest or uniform motion. Since the initial state (assuming from the context of a tug - of - war at rest before significant movement) and $F_{net}=0$, there is no motion.

# Answer:
IS NO

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QUESTION IMAGE

Question

Explanation:

6.

a.

Step1: Determine the direction of forces

Step2: Calculate the net force

Step1: Determine the direction of forces

Step2: Calculate the net force

Answer:

b.