Question

a basketball player, ava, trackers her free throw statistics over three months of the season. the table shows the number of free throws she made versus the total attempts.
part a - create a percent proportion to represent the percentage of free throws made out of her total attempts across all three periods.
part b - what percentage of her total free throw attempts did ava miss? round your answer to the nearest percent.

Explanation:

Step1: Calculate total free throws made and total attempts

Total free throws made: \(40 + 39+55=134\)
Total attempts: \(50 + 60+80 = 190\)

Step2: Set up the proportion for made free - throws

Let \(p\) be the percentage of free throws made. The proportion is \(\frac{134}{190}=\frac{p}{100}\)

Step3: Calculate the percentage of made free - throws

Cross - multiply: \(190p=134\times100\), so \(p=\frac{134\times100}{190}\approx70.53\%\)

Step4: Calculate the percentage of missed free - throws

Since the percentage of made free - throws is approximately \(70.53\%\), the percentage of missed free - throws is \(100 - 70.53=29.47\%\approx29\%\)

Answer:

Part A: \(\frac{134}{190}=\frac{p}{100}\)
Part B: \(29\%\)