Question

based on the velocity vs. time graph below, how can the acceleration between 0 and 5 seconds be determined? (acceleration = change in velocity / change in time) graph 3: velocity vs time v (m/s) t (s) options: (10 - 10) meters per second / (15 - 5) seconds; (10 - 0) meters per second / (5 - 0) seconds; (0 - 10) meters per second / (5 - 0) seconds; (10 - 0) meters per second / (0 - 5) seconds

Explanation:

Step1: Recall acceleration formula

Acceleration is $\frac{\text{change in velocity}}{\text{change in time}}$, where change in velocity = final velocity - initial velocity, change in time = final time - initial time.

Step2: Identify initial and final values

At \( t = 0 \) s, velocity \( v_0 = 0 \) m/s. At \( t = 5 \) s, velocity \( v_5 = 10 \) m/s.

Step3: Calculate change in velocity and time

Change in velocity: \( 10 - 0 \) m/s. Change in time: \( 5 - 0 \) s.

Step4: Match with options

The formula becomes \( \frac{(10 - 0)\text{ m/s}}{(5 - 0)\text{ seconds}} \), which matches the second option.

Answer:

B. (10 - 0) meters per second / (5 - 0) seconds (assuming the second option is labeled as such; if options are A, B, C, D, then the correct option is the one with (10 - 0) m/s / (5 - 0) s)