Question

balancing equations workshop

1. __ kno₃ + h₂co₃ → k₂co₃ + __ hno₃

Explanation:

Step1: Balance potassium atoms

Let the coefficient of \(KNO_3\) be \(x\) and of \(K_2CO_3\) be \(y\). For potassium (\(K\)) atoms: \(x = 2y\). Let \(y = 1\), then \(x=2\).
So far: \(2KNO_3+H_2CO_3
ightarrow K_2CO_3 + HNO_3\)

Step2: Balance nitrate \((NO_3)\) and hydrogen \((H)\) atoms

For nitrate \((NO_3)\) groups: on the left - hand side from \(KNO_3\) we have \(2\) \(NO_3\) groups. On the right - hand side, if the coefficient of \(HNO_3\) is \(2\), nitrate groups are balanced.
For hydrogen \((H)\) atoms: on the left - hand side from \(H_2CO_3\) we have \(2\) \(H\) atoms. On the right - hand side, from \(HNO_3\) (with coefficient \(2\)) we have \(2\) \(H\) atoms.
Carbon and oxygen atoms are also balanced.

Answer:

\(2KNO_3 + 1H_2CO_3
ightarrow1K_2CO_3+2HNO_3\)