Question

balance the reaction, do not leave any fractions, dont leave anything blank, then answer the questions about the reaction
1 c7h14 + 2 o2 → 3 co2(g) + 4 h2o
this is an 5 reaction.
is this a redox reaction? (yes/no)6, because o2^0 is reduced to o^-2, and because c^-4 is 7 to c^+4.
will the reaction happen as it is written? (yes/no)8, because this is known to be an exothermic reaction and because co2 and h2o are 9. the reverse reaction would not happen.
a. 1 b. 2 c. 3 d. 4 e. 5 f. 6 g. 7 h. 8
i. 9 j. 10 k. 12 l. 14 m. 16 n. 18 o. 20 p. 21
q. 24 r. 26 s. 28 t. synthesis u. decomposition
v. single displacement w. double displacement x. neutralization
y. combustion z. yes aa. no bb. reactive cc. stable
dd. oxidized ee. reduced

Explanation:

Step1: Balance the carbon atoms

For \(C_7H_{14}\), there are 7 carbon atoms. So, the coefficient of \(CO_2\) should be 7.

Step2: Balance the hydrogen atoms

There are 14 hydrogen atoms in \(C_7H_{14}\). So, the coefficient of \(H_2O\) should be 7.

Step3: Balance the oxygen atoms

The right - hand side has \(7\times2 + 7\times1=21\) oxygen atoms. So, the coefficient of \(O_2\) should be \(\frac{21}{2}\). But we need to eliminate fractions. Multiply all coefficients by 2.
The balanced equation is \(2C_7H_{14}+21O_2
ightarrow14CO_2 + 14H_2O\)

Step4: Determine the reaction type

This is a combustion reaction (\(Y\)) as it is a reaction of a hydrocarbon with oxygen.

Step5: Check if it is a redox reaction

Oxidation state of \(O\) in \(O_2\) is \(0\), in \(CO_2\) and \(H_2O\) it is \(- 2\). Oxidation state of \(C\) in \(C_7H_{14}\) (assuming \(H=-1\)): \(7x+14\times(- 1)=0\), \(x = + 2\) (average). In \(CO_2\), \(C = + 4\). So, \(C\) is oxidized (\(DD\)) and \(O\) is reduced. It is a redox reaction (\(Z\))

Step6: Determine if the reaction will happen

Combustion of hydrocarbons is exothermic and \(CO_2\) and \(H_2O\) are stable (\(CC\)). So, the reaction will happen (\(Z\))

Answer:

1. \(2\)
2. \(21\)
3. \(14\)
4. \(14\)
5. \(Y\) (combustion)
6. \(Z\) (yes)
7. \(DD\) (oxidized)
8. \(Z\) (yes)
9. \(CC\) (stable)