Question

balance the equation $\ce{c5h12o2 + o2 -> co2 + h2o}$
what is the coefficient in front of oxygen?
3
5
7
8
question 48 (0.0862 points)
which substance is most likely to be miscible with water?
$\ce{cl2}$
$\ce{co2}$
$\ce{nh3}$
none of these

Explanation:

First Question (Balancing Equation)

Step1: Balance Carbon

In \( \ce{C5H12O2} \), there are 5 C atoms. So, we put a coefficient of 5 in front of \( \ce{CO2} \):
\( \ce{C5H12O2 + O2 -> 5CO2 + H2O} \)

Step2: Balance Hydrogen

There are 12 H atoms in \( \ce{C5H12O2} \). Since each \( \ce{H2O} \) has 2 H, we need \( \frac{12}{2} = 6 \) \( \ce{H2O} \):
\( \ce{C5H12O2 + O2 -> 5CO2 + 6H2O} \)

Step3: Balance Oxygen

Calculate O atoms on the right: \( 5 \times 2 + 6 \times 1 = 10 + 6 = 16 \).
O atoms in \( \ce{C5H12O2} \): 2. So, O from \( \ce{O2} \) is \( 16 - 2 = 14 \). Each \( \ce{O2} \) has 2 O, so coefficient for \( \ce{O2} \) is \( \frac{14}{2} = 7 \):
\( \ce{C5H12O2 + 7O2 -> 5CO2 + 6H2O} \)

Miscibility with water depends on polarity (like dissolves like). \( \ce{NH3} \) is polar and forms hydrogen bonds with water, making it highly miscible. \( \ce{Cl2} \) is nonpolar, and \( \ce{CO2} \) is only slightly soluble (not miscible).

Answer:

7

Second Question (Miscibility with Water)