Question

1. balance the equation for propane ($c_3h_8$) is burned. by dragging coefficients.

i need a hint
$\

$$\begin{array}{r} ?\\ c_3h_8+?\\ o_2\\to ?\\ co_2+?\\ h_2o\\end{array}$$

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Explanation:

Step1: Balance Carbon atoms

In \( \ce{C3H8} \), there are 3 C atoms. So, we need 3 \( \ce{CO2} \) to balance C. So coefficient of \( \ce{CO2} \) is 3.
\( \ce{C3H8 + O2 -> 3CO2 + H2O} \)

Step2: Balance Hydrogen atoms

In \( \ce{C3H8} \), there are 8 H atoms. Each \( \ce{H2O} \) has 2 H atoms. So, number of \( \ce{H2O} \) molecules needed is \( \frac{8}{2} = 4 \). So coefficient of \( \ce{H2O} \) is 4.
\( \ce{C3H8 + O2 -> 3CO2 + 4H2O} \)

Step3: Balance Oxygen atoms

On the right side, \( 3\ce{CO2} \) has \( 3\times2 = 6 \) O atoms and \( 4\ce{H2O} \) has \( 4\times1 = 4 \) O atoms. Total O atoms on right: \( 6 + 4 = 10 \). Each \( \ce{O2} \) has 2 O atoms. So, coefficient of \( \ce{O2} \) is \( \frac{10}{2}=5 \).
\( \ce{C3H8 + 5O2 -> 3CO2 + 4H2O} \)

Step4: Check Propane coefficient

The coefficient of \( \ce{C3H8} \) remains 1 as we started with 1 molecule of propane.

Answer:

The balanced equation is \( \boldsymbol{1}\ce{C3H8 + 5O2 -> 3CO2 + 4H2O} \), so the coefficients are 1 (for \( \ce{C3H8} \)), 5 (for \( \ce{O2} \)), 3 (for \( \ce{CO2} \)), and 4 (for \( \ce{H2O} \)).