Question

balance this equation, _n₂+_o₂→_h₂o+_hno₃ not possible 2,2,1,4 2,1,1,4 2,2,1,2

Explanation:

Step1: Check the number of each element

Let the coefficients be \(a\), \(b\), \(c\), \(d\) for \(N_2\), \(O_2\), \(H_2O\), \(HNO_3\) respectively.
For \(N\): \(2a=d\)
For \(H\): \(2c = d\)
For \(O\): \(2b=c + 3d\)

Step2: Substitute and solve

From \(2a=d\) and \(2c = d\), we have \(a = c\).
Substitute \(d = 2a\) and \(c=a\) into \(2b=c + 3d\), we get \(2b=a+3\times2a=7a\).
Let \(a = 2\), then \(b = 7\), \(c = 2\), \(d = 4\). But there is no such option.
Let's check the options:
For option \(2,11,4\):
Left side: \(N:2\times2 = 4\), \(O:11\times2=22\)
Right side: \(H:4\times2 = 8\), \(N:4\times1 = 4\), \(O:4\times1+4\times3=16\) (wrong)
For option \(2,2,1,4\):
Left side: \(N:2\times2 = 4\), \(O:2\times2 = 4\)
Right side: \(H:1\times2=2\), \(N:4\times1 = 4\), \(O:1\times1+4\times3=13\) (wrong)
For option \(2,2,1,2\):
Left side: \(N:2\times2 = 4\), \(O:2\times2 = 4\)
Right side: \(H:1\times2=2\), \(N:2\times1 = 2\) (wrong)

Answer:

not possible