Question

balance the chemical equation by selecting the appropriate coefficient for each substance. enter 1 if the coefficient is 1. do not leave it blank. a. b. c. d. e. f. g. h. fes(s) + o₂(g) → fe₂o₃(s) + so₂(g) 1. 1 2. 2 3. 3 4. 4 5. 5 6. 6 7. 7 8. 8

Explanation:

Step1: Balance Fe atoms

In \(FeS\) and \(Fe_2O_3\), to balance Fe, if we put 4 in front of \(FeS\) (so 4 Fe atoms on left), we put 2 in front of \(Fe_2O_3\) (2×2 = 4 Fe atoms on right).
\(4FeS(s)+O_2(g)\to2Fe_2O_3(s)+SO_2(g)\)

Step2: Balance S atoms

Since there are 4 S atoms in \(4FeS\), we put 4 in front of \(SO_2\) (4 S atoms on right).
\(4FeS(s)+O_2(g)\to2Fe_2O_3(s)+4SO_2(g)\)

Step3: Balance O atoms

On the right - hand side, in \(2Fe_2O_3\) there are \(2\times3 = 6\) O atoms and in \(4SO_2\) there are \(4\times2=8\) O atoms. So total O atoms on right are \(6 + 8=14\). On the left - hand side, if we let the coefficient of \(O_2\) be \(x\), then \(2x = 14\), so \(x = 7\).

Answer:

\(4FeS(s)+7O_2(g)\to2Fe_2O_3(s)+4SO_2(g)\)
So the coefficients are: \(FeS = 4\), \(O_2=7\), \(Fe_2O_3 = 2\), \(SO_2=4\)