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3. to avoid tailgating, and help avoid a rear - end collision, you shou…

Question

  1. to avoid tailgating, and help avoid a rear - end collision, you should give yourself a gap of how many seconds behind the car in front of you?

a. 5 seconds
b. 10 seconds
c. 7 seconds
d. 3 seconds

  1. if you are distracted for one second, by a cell phone, passenger, or other distraction, at 30 mph you will travel how far \blindly\?

a. 30 feet
b. 45 feet
c. 60 feet
d. 90 feet

Explanation:

Step1: Convert miles per hour to feet per second

We know that 1 mile = 5280 feet and 1 hour = 3600 seconds.
To convert \(v = 30\) mph to feet per second, we use the formula \(v=\frac{30\times5280}{3600}\)

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But a common rule - of - thumb conversion: \(1\) mph=\(\frac{5280}{3600}= 1.4667\) feet per second. So for \(v = 30\) mph, \(v=30\times1.4667 = 44\) feet per second (approx). Another way: \(30\) mph means in 1 hour (3600 seconds) you go 30 miles (30\times5280 feet). In 1 second, distance \(d=\frac{30\times5280}{3600}=44\) feet (approx). But if we use the formula \(d = vt\), where \(t = 1\) second.

If we consider the following:
We know that \(1\) mile \(=5280\) feet. So \(30\) miles \(=30\times5280\) feet. And \(1\) hour \(=3600\) seconds.
The speed \(v\) in feet per second is \(v=\frac{30\times5280}{3600}\)

$$v=\frac{158400}{3600}=44\approx45\text{ (when rounded)}$$

Step2: Calculate the distance traveled in 1 second

Using the formula \(d=v\times t\), where \(v\) is the speed and \(t\) is the time. Given \(t = 1\) second and \(v\approx45\) feet per second (after rounding the conversion result of \(30\) mph to feet per second more closely to the options)

Answer:

For question 3: D. 3 seconds (a common rule - of - thumb for following distance to avoid tailgating).
For question 4: B. 45 feet.