Question

1. an astronaut uses a small jet pack that applies a constant force of 20 n to propel a 120 kg repair unit in space. what is the acceleration of the repair unit

Explanation:

Step1: Identify given and unknown

Given: \(F = 20\space N\), \(m=120\space kg\)
Unknown: \(a\) (acceleration)
Equation: \(F = ma\) (Newton's second law)

Step2: Solve for \(a\)

From \(F = ma\), we can express \(a\) as \(a=\frac{F}{m}\)
Substitute \(F = 20\space N\) and \(m = 120\space kg\) into the formula: \(a=\frac{20}{120}\space m/s^{2}\)

Step3: Simplify

\(a=\frac{1}{6}\space m/s^{2}\approx0.17\space m/s^{2}\)

Answer:

Given: \(F = 20\space N\), \(m = 120\space kg\); Unknown: \(a\); Equation: \(F=ma\); Substitute: \(a=\frac{20}{120}\space m/s^{2}\); Solve: \(a\approx0.17\space m/s^{2}\)