Question

(a) assuming the roof and doors require no paint, what is the area in square feet that needs paint? (do not round any intermediate computations and give your answer as a whole number.)
4011 ft²
(b) the paint to be used is sold in cans. each can contains enough paint to cover 580 ft². assume there is no paint yet and partial cans cannot be bought. how many cans will need to be bought in order to paint the warehouse?
7 cans
(c) what is the total cost of the paint needed for the warehouse if each can costs $40.50?
$162
try again

Explanation:

Step1: Calculate the number of cans

We know the area to be painted is \(4011\ \text{ft}^2\) and each can covers \(580\ \text{ft}^2\). We use the formula \(n=\frac{A}{a}\), where \(A = 4011\) (total area) and \(a=580\) (area per can). So \(n=\frac{4011}{580}\approx6.9155\). Since partial - cans cannot be bought, we use the ceiling function. So \(n = 7\) cans.

Step2: Calculate the total cost

If each can costs \(C=\$40.50\) and the number of cans \(n = 7\), then the total cost \(T=n\times C\). Substitute \(n = 7\) and \(C = 40.50\) into the formula: \(T=7\times40.50=283.5\)

Answer:

The total cost of the paint is \(\$283.5\)