Question

1. assume that one of squidward’s sons, who is heterozygous for the light blue body color, married a girl that was also heterozygous. create a punnett square to show the possibilities that would result if they had children. a. list the possible genotypes and phenotypes for their children. g: ____________ p: __________ b. what are the chances of a child with light blue skin? __________ out of __________ or __________ % c. what are the chances of a child with light green skin? __________ out of __________ or ____________ %

Explanation:

Step1: Define alleles

Let's assume the allele for light - blue body color is $B$ and the allele for light - green body color is $b$. Both parents are heterozygous, so their genotype is $Bb$.

Step2: Create Punnett square

	B	b
b	Bb	bb

Step3: Determine genotypes and phenotypes

• Genotypes: $BB:Bb:bb = 1:2:1$.
• Phenotypes: Since $B$ is dominant over $b$, the phenotype for $BB$ and $Bb$ is light - blue body color and the phenotype for $bb$ is light - green body color. So, light - blue : light - green = 3:1.

Step4: Calculate probabilities

• For light - blue skin: There are 3 genotypes ($BB$, $Bb$, $Bb$) out of 4 that result in light - blue skin. So the probability is $\frac{3}{4}$ or 75%.
• For light - green skin: There is 1 genotype ($bb$) out of 4 that results in light - green skin. So the probability is $\frac{1}{4}$ or 25%.

Answer:

A. Genotypes: $BB$, $Bb$, $bb$. Phenotypes: Light - blue body color, light - green body color.
B. 3 out of 4 or 75%
C. 1 out of 4 or 25%