Question

the area of a square poster is 50 in². find the length of one side of the poster to the nearest tenth of an inch. (round to the nearest tenth as needed)

Explanation:

Step1: Recall square - area formula

Let the side length of the square be $s$. The area formula of a square is $A = s^{2}$, where $A = 50$ in².

Step2: Solve for side - length

$s=\sqrt{A}=\sqrt{50}\approx7.1$ in

Answer:

7.1 in