Question

an area reserved for a parking lot is 80 feet long and 77 feet wide. the stalls of the lot are at 90° angles to two one - way aisles. each aisle is 80 feet by 10 feet. the three areas set aside for the parking spaces are congruent rectangles. each parking space will be 19 feet by 8 feet. what is the maximum number of parking spaces that will fit in the lot? 10 30 35 40

Explanation:

Step1: Calculate the total width of the two aisles

Each aisle is \(10\) feet wide. There are \(2\) aisles.
The total width of the aisles is \(2\times10 = 20\) feet.

Step2: Calculate the total width available for parking spaces

The total width of the parking - lot area is \(77\) feet.
The width available for parking spaces is \(77−20=57\) feet.

Step3: Calculate the number of parking spaces in the width - direction

Each parking space is \(19\) feet wide.
The number of parking spaces in the width - direction is \(\frac{57}{19}=3\).

Step4: Calculate the number of parking spaces in the length - direction

The length of the parking - lot area (and the length of each parking space) is \(80\) feet. Each parking space is \(8\) feet in the other dimension.
The number of parking spaces in the length - direction is \(\frac{80}{8}=10\).

Step5: Calculate the total number of parking spaces

Since there are \(3\) groups of parking spaces (because of the two aisles dividing the parking area into three congruent rectangles) and each group has \(10\) parking spaces in the length - direction.
The total number of parking spaces is \(3\times10 = 30\).

Answer:

\(30\)