Question

architecture class: $5 initial fee $13 per session initial value for architecture class: 5 rate of change for architecture class: 13 complete the table for architecture. number of sessions 0 1 2 3 4 total cost for architecture($) 5 drawing class: number of sessions 0 1 2 3 4 total cost ($) 0 16 32 48 64 initial value for drawing class: 0 rate of change for drawing class: 16

Explanation:

Step1: Define the cost formula

The cost for architecture class is given by the linear equation \( C = 5 + 13n \), where \( n \) is the number of sessions and \( C \) is the total cost.

Step2: Calculate for n=1

Substitute \( n = 1 \) into the formula: \( C = 5 + 13(1) = 5 + 13 = 18 \).

Step3: Calculate for n=2

Substitute \( n = 2 \): \( C = 5 + 13(2) = 5 + 26 = 31 \).

Step4: Calculate for n=3

Substitute \( n = 3 \): \( C = 5 + 13(3) = 5 + 39 = 44 \).

Step5: Calculate for n=4

Substitute \( n = 4 \): \( C = 5 + 13(4) = 5 + 52 = 57 \).

Answer:

The completed table for architecture class (Number of Sessions: 0,1,2,3,4; Total Cost: 5, 18, 31, 44, 57). So the values for sessions 1 - 4 are 18, 31, 44, 57 respectively.