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Question
if \\( \angle a \cong \angle c \\), and \\( \angle b \cong \angle c \\), then
your answer
if \\( \angle 6 \\) is supplementary to \\( \angle 9 \\), and \\( \angle 3 \\) is supplementary to \\( \angle 9 \\), then
your answer
if \\( \angle 5 \\) and \\( \angle 12 \\) form a linear pair, and \\( \angle 4 \\) and \\( \angle 12 \\) form a linear pair,
then
First problem:
Step1: Use the transitive property of congruence
If \( \angle A\cong\angle C\) and \( \angle B\cong\angle C\), by the transitive property of congruence (if \(a = c\) and \(b = c\), then \(a = b\)), we can say \( \angle A\cong\angle B\)
Second problem:
Step1: Use the congruent supplements theorem
If two angles are supplementary to the same angle, then they are congruent. Since \( \angle6\) is supplementary to \( \angle9\) (\(\angle6+\angle9 = 180^{\circ}\)) and \( \angle3\) is supplementary to \( \angle9\) (\(\angle3+\angle9=180^{\circ}\)), then \( \angle6\cong\angle3\)
Third problem:
Step1: Use the congruent - linear - pairs theorem
If two angles form a linear pair with the same angle, then they are congruent. Since \( \angle5\) and \( \angle12\) form a linear pair (\(\angle5+\angle12 = 180^{\circ}\)) and \( \angle4\) and \( \angle12\) form a linear pair (\(\angle4+\angle12=180^{\circ}\)), then \( \angle5\cong\angle4\)
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- \( \angle A\cong\angle B\)
- \( \angle6\cong\angle3\)
- \( \angle5\cong\angle4\)