Question

answer the question based upon the reaction below: (nh₄)₂cro₄(aq) + 2agno₃(aq) -> ag₂cro₄(s) + 2nh₄no₃(aq) identify the type of reaction. single displacement oxidation reduction double displacement acid - base reaction 5 multiple choice 2 points answer the question based upon the reaction below: (nh₄)₂cro₄(aq) + 2agno₃(aq) -> ag₂cro₄(s) + 2nh₄no₃(aq) what is the net ionic equation for the reaction? a. nh₄⁺(aq) + no₃⁻(aq) -> nh₄no₃(aq) b. nh₄⁺(aq) + ag⁺(aq) -> agnh₄²⁺(s) c. cro₄²⁻(aq) + 2ag⁺(aq) -> ag₂cro₄(s) d. (nh₄)₂cro₄(aq) + 2agno₃(aq) -> ag₂cro₄(s) + 2nh₄no₃(aq) a b c d

Explanation:

Step1: Write the complete ionic equation

$$(NH_4)_2CrO_4(aq)=2NH_4^{+}(aq)+CrO_4^{2 - }(aq)$$
$$2AgNO_3(aq)=2Ag^{+}(aq)+2NO_3^{-}(aq)$$
$$2NH_4NO_3(aq)=2NH_4^{+}(aq)+2NO_3^{-}(aq)$$
The complete ionic equation is:
$$2NH_4^{+}(aq)+CrO_4^{2 - }(aq)+2Ag^{+}(aq)+2NO_3^{-}(aq)\to Ag_2CrO_4(s)+2NH_4^{+}(aq)+2NO_3^{-}(aq)$$

Step2: Cancel the spectator ions

Spectator ions are \(NH_4^{+}(aq)\) and \(NO_3^{-}(aq)\) which appear on both sides of the complete ionic equation.
After canceling them, the net - ionic equation is:
$$CrO_4^{2 - }(aq)+2Ag^{+}(aq)\to Ag_2CrO_4(s)$$

Answer:

C. \(CrO_4^{2 - }(aq)+2Ag^{+}(aq)\to Ag_2CrO_4(s)\)