Question

the amount of potential energy, p, an object has is equal to the product of its mass, m, its height off the ground, h, and the gravitational constant, g. this can be modeled by the equation p = mgh. what is the equivalent equation solved for h?
options:
\\(\frac{\left(\frac{p}{m}\
ight)}{g} = h\\)
\\(\frac{p}{mg} = h\\)
\\(pmg = h\\)
\\(\frac{p}{\left(\frac{m}{g}\
ight)} = h\\)

Explanation:

Step1: Start with the formula \( P = mgh \)

We need to solve for \( h \), so we want to isolate \( h \) on one side of the equation.

Step2: Divide both sides by \( mg \)

To isolate \( h \), we divide both sides of the equation \( P = mgh \) by \( mg \) (assuming \( m
eq 0 \) and \( g
eq 0 \)).
\[
\frac{P}{mg}=\frac{mgh}{mg}
\]
Simplifying the right - hand side, the \( m \) and \( g \) in the numerator and denominator cancel out, leaving us with \( h \). So \( \frac{P}{mg}=h \)

Answer:

\(\boldsymbol{\frac{P}{mg}=h}\) (corresponding to the option \(\frac{P}{mg}=h\))