Question

always use significant figure rules. remember that these rules apply to all numbers that are measurements.
the impulse given to a ball with mass of 2.0 kg is 16 n*s. if the ball were already moving at 3.0 m/s, what would the final
velocity be? (remember that ( delta v = v_{\text{final}} - v_{\text{initial}} ) )
11 m/s
5 m/s
25 m/s
29 m/s

Explanation:

Step1: Usar la fórmula del impulso

El impulso \( J = m\Delta v\), donde \(J = 16\space N\cdot s\), \(m = 2.0\space kg\). Entonces \(\Delta v=\frac{J}{m}\)

$$ \Delta v=\frac{16}{2.0}=8.0\space m/s $$

Step2: Calcular la velocidad final

Sabemos que \(\Delta v = v_{final}-v_{initial}\), \(v_{initial} = 3.0\space m/s\) y \(\Delta v = 8.0\space m/s\). Entonces \(v_{final}=\Delta v + v_{initial}\)

$$ v_{final}=8.0 + 3.0=11\space m/s $$

Answer:

11 m/s