Question

algebra 1 - the distance formula and midpoint formu... do the coordinate points form a right triangle? use the distance formu and the pythagorean theorem to prove your answer. d of ab = √((-2 - 0)^2+(-3 - 5)^2)=√((2)^2+(-8)^2)=√(4 + 64)=√68=√4√17 = 2√17 d of bc = √((2 - 2)^2+(-2 - 3)^2) d of ca = mp of ab = question 8 06:22 question 9 07:05 9. what is the distance between (-2,-3) and (2,-2) * required 1 1 √2 5 √17

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Step2: Identify points

Let $(x_1,y_1)=(-2,-3)$ and $(x_2,y_2)=(2,-2)$.

Step3: Substitute values

$d=\sqrt{(2 - (-2))^2+((-2)-(-3))^2}=\sqrt{(2 + 2)^2+(-2 + 3)^2}=\sqrt{4^2+1^2}=\sqrt{16 + 1}=\sqrt{17}$.

Answer:

D. $\sqrt{17}$