Question

1)___albr₃ +_k→_kbr +___al

Explanation:

Step1: Balance bromine atoms

In \(AlBr_3\) there are 3 bromine atoms. In \(KBr\), there is 1 bromine atom. So we put a 3 in front of \(KBr\).
\(AlBr_3+K
ightarrow3KBr + Al\)

Step2: Balance potassium atoms

After putting 3 in front of \(KBr\), there are 3 potassium atoms on the right - hand side. So we put a 3 in front of \(K\).
\(AlBr_3 + 3K
ightarrow3KBr+Al\)

Step3: Check aluminum atoms

There is 1 aluminum atom on both sides.

Answer:

\(1AlBr_3+3K
ightarrow3KBr + 1Al\)