Question

agno₃ + k₂so₄ → ag₂so₄ + kno₃

Explanation:

Step1: Identify reactants and products

Reactants: $\ce{AgNO_{3}}$, $\ce{K_{2}SO_{4}}$; Products: $\ce{Ag_{2}SO_{4}}$, $\ce{KNO_{3}}$

Step2: Balance Ag atoms

Left: 1 Ag; Right: 2 Ag. So put 2 in front of $\ce{AgNO_{3}}$: $2\ce{AgNO_{3}} + \ce{K_{2}SO_{4}}
ightarrow \ce{Ag_{2}SO_{4}} + \ce{KNO_{3}}$

Step3: Balance K atoms

Left: 2 K (from $\ce{K_{2}SO_{4}}$); Right: 1 K (from $\ce{KNO_{3}}$). So put 2 in front of $\ce{KNO_{3}}$: $2\ce{AgNO_{3}} + \ce{K_{2}SO_{4}}
ightarrow \ce{Ag_{2}SO_{4}} + 2\ce{KNO_{3}}$

Step4: Check other atoms (S, N, O)

S: 1 on left (from $\ce{K_{2}SO_{4}}$) and 1 on right (from $\ce{Ag_{2}SO_{4}}$) – balanced.
N: 2 on left (from $2\ce{AgNO_{3}}$) and 2 on right (from $2\ce{KNO_{3}}$) – balanced.
O: 6 (from $2\ce{AgNO_{3}}$) + 4 (from $\ce{K_{2}SO_{4}}$) = 10; 4 (from $\ce{Ag_{2}SO_{4}}$) + 6 (from $2\ce{KNO_{3}}$) = 10 – balanced.

Answer:

$2\ce{AgNO_{3}} + \ce{K_{2}SO_{4}} = \ce{Ag_{2}SO_{4}} + 2\ce{KNO_{3}}$