Question

add. (6c³ + 3c² + 4c - 9) + (2c² + 4c)

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. The expression becomes \(6c^{3}+3c^{2}+4c - 9+2c^{2}+4c\).

Step2: Combine like terms

• For the \(c^{3}\) term: There is only \(6c^{3}\), so it remains \(6c^{3}\).
• For the \(c^{2}\) terms: We have \(3c^{2}\) and \(2c^{2}\). Combining them, we get \(3c^{2}+2c^{2}=5c^{2}\).
• For the \(c\) terms: We have \(4c\) and \(4c\). Combining them, we get \(4c + 4c=8c\).
• For the constant term: There is only \(-9\), so it remains \(-9\).

Putting it all together, we have \(6c^{3}+5c^{2}+8c - 9\).

Answer:

\(6c^{3}+5c^{2}+8c - 9\)