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adair advertising has 2 spherical balloons. one has a radius of 3 feet …

Question

adair advertising has 2 spherical balloons. one has a radius of 3 feet and the other one has a radius of 5 feet. what is the difference in the volume of the two balloons, rounded to the nearest tenth of a cubic foot? use 3.14 for π. 201.1 ft³ 410.3 ft³ 205.3 ft³ 67.0 ft³

Explanation:

Step1: Recall the volume formula for a sphere.

The volume \( V \) of a sphere is given by the formula \( V = \frac{4}{3}\pi r^3 \), where \( r \) is the radius of the sphere.

Step2: Calculate the volume of the first balloon (radius \( r_1 = 3 \) feet).

Substitute \( r = 3 \) and \( \pi = 3.14 \) into the formula:

$$ LATEXBLOCK0 $$

Step3: Calculate the volume of the second balloon (radius \( r_2 = 5 \) feet).

Substitute \( r = 5 \) and \( \pi = 3.14 \) into the formula:

$$ LATEXBLOCK1 $$

Step4: Find the difference in volumes.

Subtract the volume of the smaller balloon from the volume of the larger balloon:

$$ LATEXBLOCK2 $$

Answer:

410.3 \( \text{ft}^3 \) (the option with 410.3 \( \text{ft}^3 \))