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a2. reflect all of the coordinates from the previous slide over the y -…

Question

a2. reflect all of the coordinates from the previous slide over the y - axis and state the coordinates below.

Explanation:

Step1: Recall the reflection rule over the y - axis

When reflecting a point \((x,y)\) over the \(y\) - axis, the rule is \((x,y)\to(-x,y)\).

Step2: Apply the rule to each coordinate

  • For the point \((-6,5)\): Using the rule \((x,y)\to(-x,y)\), we substitute \(x=-6\) and \(y = 5\). Then \(-x=-(-6)=6\), so the new coordinate is \((6,5)\).
  • For the point \((-3,8)\): Substitute \(x = - 3\) and \(y=8\) into the rule. Then \(-x=-(-3)=3\), so the new coordinate is \((3,8)\).
  • For the point \((0,8)\): Substitute \(x = 0\) and \(y = 8\) into the rule. Then \(-x=-0 = 0\), so the new coordinate is \((0,8)\).
  • For the point \((0,-2)\): Substitute \(x = 0\) and \(y=-2\) into the rule. Then \(-x=-0 = 0\), so the new coordinate is \((0,-2)\).
  • For the point \((-3,-2)\): Substitute \(x=-3\) and \(y = - 2\) into the rule. Then \(-x=-(-3)=3\), so the new coordinate is \((3,-2)\).
  • For the point \((-6,-1)\): Substitute \(x=-6\) and \(y=-1\) into the rule. Then \(-x=-(-6)=6\), so the new coordinate is \((6,-1)\).

Answer:

New XNew Y
\(3\)\(8\)
\(0\)\(8\)
\(0\)\(-2\)
\(3\)\(-2\)
\(6\)\(-1\)