Question

1. a 9kg motorcyclist is driving off of a cliff for a stunt, and has a constant horizontal acceleration of 4.5 m/s^2 from his gas pedal. as he is falling off of the cliff, what is the net force acting on him?

Explanation:

Step1: Recall Newton's Second Law

Newton's second law states that the net force \( F_{net} \) acting on an object is equal to the mass \( m \) of the object multiplied by its acceleration \( a \), i.e., \( F_{net}=m\times a \).

Step2: Identify given values

The mass \( m \) of the motorcyclist is \( 9\space kg \) and the horizontal acceleration \( a \) is \( 4.5\space m/s^2 \).

Step3: Calculate the net force

Substitute the values of \( m \) and \( a \) into the formula \( F_{net}=m\times a \). So, \( F_{net}=9\space kg\times4.5\space m/s^2 \). Calculating this, we get \( F_{net} = 40.5\space N \).

Answer:

The net force acting on the motorcyclist is \( \boldsymbol{40.5\space N} \).