Question

1. (912.ar.1.2) the perimeter of any rectangle in which the length is 4 more than twice the width is p = 6w + 8, where w is the width. which formula can be used to find the width given the perimeter? a. w = p - 4/3 b. w = 1/6p - 8 c. w = -(p + 8)/6 d. w = (p - 8)/6

Explanation:

Step1: Isolate the term with w

Given $P = 6w+8$, subtract 8 from both sides: $P - 8=6w$.

Step2: Solve for w

Divide both sides by 6: $w=\frac{P - 8}{6}$.

Answer:

D. $w=\frac{P - 8}{6}$