Question

5.1.89
11 parts | 0.05 of 1 point
part 2 of 11
beginning with \\((f^{-1} \circ f)(x)\\).
\\((f^{-1} \circ f)(x) = \\) select

Explanation:

Apply function composition definition

Using the Composition of Functions knowledge point

$$ (f^{-1} \circ f)(x) = f^{-1}(f(x)) $$

Simplify the composed expression

Using the Inverse Functions knowledge point

$$ f^{-1}(f(x)) = x $$

Answer:

Beginning with \((f^{-1} \circ f)(x)\).

\((f^{-1} \circ f)(x) =\) <blank>\(f^{-1}(f(x))\)</blank> \(=\) <blank>\(x\)</blank>