QUESTION IMAGE
Question
- (1,5) ;
-7m + 8n = 33
- (-2,0) ; 50 = -9x - 2y
(7, -4) ;
9b + 4a = -8
6a + 5b - 42 = 0
- (-3,-2) ;
-7c - 4d = 29
3c = -7 + d
b) check whether (6, 9) is a solution of the systems of linear equations.
- s + 7t = 69
6t + 4s = 78
- -2p + 5q = 34
-7q = -61 - 8p
c) write a system of linear equations that has the solution (4, 3).
Part 1: Verify given points as solutions
Step1: Check (1,5) in eq1
Substitute $m=1, n=5$ into $-7m+8n=33$:
Step2: Confirm (1,5) is solution
Both sides equal, so it is a solution.
Step3: Check (-2,0) in eq2
Substitute $x=-2, y=0$ into $50=-9x-2y$:
Step4: Confirm (-2,0) not solution
Sides not equal, so not a solution.
Step5: Check (7,-4) in eq3
Substitute $a=7, b=-4$ into $9b+4a=-8$:
Substitute into $6a+5b-42=0$:
Step6: Confirm (7,-4) not solution
Fails second equation, so no.
Step7: Check (-3,-2) in eq4
Substitute $c=-3, d=-2$ into $-7c-4d=29$:
Substitute into $3c=-7+d$:
Step8: Confirm (-3,-2) is solution
Both equations hold, so yes.
Step1: Check (6,9) in system 5
Substitute $s=6, t=9$ into $s+7t=69$:
Substitute into $6t+4s=78$:
Step2: Confirm (6,9) for system5
Both equations hold, so yes.
Step3: Check (6,9) in system6
Substitute $p=6, q=9$ into $-2p+5q=34$:
Step4: Confirm (6,9) for system6
Fails first equation, so no.
Step1: Create first linear equation
Use $x+y=k$, substitute $x=4,y=3$: $4+3=7$, so $x+y=7$.
Step2: Create second linear equation
Use $x-y=k$, substitute $x=4,y=3$: $4-3=1$, so $x-y=1$.
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