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6x² - 54 = 0

Question

6x² - 54 = 0

Explanation:

Step1: Isolate the \(x^2\) term

First, we add 54 to both sides of the equation \(6x^2 - 54 = 0\) to get \(6x^2 = 54\). Then, we divide both sides by 6: \(\frac{6x^2}{6}=\frac{54}{6}\), which simplifies to \(x^2 = 9\).

Step2: Solve for \(x\)

Taking the square root of both sides, we know that if \(x^2 = 9\), then \(x=\pm\sqrt{9}\). Since \(\sqrt{9} = 3\), we have \(x = 3\) or \(x=- 3\).

Answer:

\(x = 3\) or \(x=-3\)