Question

3x + 50 ≤ 5
-30 -25 -20 -15 -10 -5 0 5 10 15 20 25 30
x < -15
-30 -25 -20 -15 -10 -5 0 5 10 15 20 25 30
x ≥ -15
-30 -25 -20 -15 -10 -5 0 5 10 15 20 25 30
x ≤ -15
-30 -25 -20 -15 -10 -5 0 5 10 15 20 25 30
x > -15

Explanation:

Step1: Isolate the term with x

Subtract 50 from both sides of the inequality $3x + 50\leq5$.
$3x+50 - 50\leq5 - 50$
$3x\leq - 45$

Step2: Solve for x

Divide both sides of the inequality $3x\leq - 45$ by 3.
$\frac{3x}{3}\leq\frac{-45}{3}$
$x\leq - 15$

Answer:

$x\leq - 15$ (corresponds to the option where there is a closed - circle at - 15 and the arrow points to the left on the number line)