Question

(3s + 4t)(3s - 4t) = \square (simplify your answer.)

Explanation:

Step1: Apply difference of squares rule

Recall the identity $(a+b)(a-b)=a^2-b^2$. Here, $a=3s$, $b=4d$.

Step2: Compute $a^2$ and $b^2$

$a^2=(3s)^2=9s^2$, $b^2=(4d)^2=16d^2$

Step3: Substitute into the identity

$(3s+4d)(3s-4d)=9s^2-16d^2$

Answer:

$9s^2 - 16d^2$