Question

3h₂so₄ + 2b(oh)₃ → b₂(so₄)₃ + 6h₂o
what is the numerator of the mole ratio between boron sulfate and sulfuric acid?
? mol b₂(so₄)₃
mol h₂so₄
fill in the green blank.

Explanation:

Step1: Analyze the balanced chemical equation

The balanced chemical equation is \(3H_2SO_4 + 2B(OH)_3
ightarrow B_2(SO_4)_3 + 6H_2O\).

Step2: Determine the mole ratio

The mole ratio of \(B_2(SO_4)_3\) to \(H_2SO_4\) is based on their coefficients in the balanced equation. The coefficient of \(B_2(SO_4)_3\) is \(1\) and the coefficient of \(H_2SO_4\) is \(3\). So the mole ratio is \(\frac{1\space mol\space B_2(SO_4)_3}{3\space mol\space H_2SO_4}\).

Answer:

\(1\)