Question

1. ranking task rank the position - time graphs according to the average speed, from greatest average speed to least average speed. specifically indicate any ties.
2. contrast average velocities describe differences in the average velocities shown on the graph for objects a and b. describe differences in the average velocities shown on the graph for objects c and d.
3. ranking task rank the graphs in figure 25 according to each objects initial position, from most positive position to most negative position. specifically indicate any ties. would your ranking be different if you ranked according to initial distance from the origin?

Explanation:

Step1: Determine average speed (magnitude of slope)

Average speed = |displacement|/time = |slope|. Steeper slope → higher speed. Assume B and C have same slope magnitude, then A, then D.

Step2: Rank average speeds

B = C > A > D

Average velocity is displacement/time (vector). A and B: A has negative velocity, B positive (opposite directions). C and D: C has negative velocity, D positive (opposite directions).

Step1: Identify initial positions (t=0)

Assume initial positions: A (3m), D (2m), B (1m), C (-1m). Rank: A > D > B > C.

Step2: Compare initial distance (absolute value)

Distances: A (3m), D (2m), B (1m), C (1m). Rank: A > D > B = C (different from position ranking).

Answer:

B = C > A > D