36. how many protons, neutrons, and electrons are located in the following elements?
| | protons | neutrons | electrons |
| --- | --- | --- | --- |
| a. chlorine | | | |
| b. neon | | | |
37. find the molar mass of the following compounds- use correct units!
a. mgco₃
b. ni(no₃)₂
know the polyatomic ions!!!!
38. name the following ionic compounds including a metal and a nonmetal or a polyatomic ion.
if the second element is a nonmetal, it ends with -ide
if the second element is a polyatomic ion, it ends with the name of the polyatomic ion
if the metal is a transition metal, the name includes the charge in roman numerals. figure out the charge
of the transition metal by using the charge of the nonmetal or the polyatomic ion.
- kf
- nio
- cuse
- limno₄
- agoh
39 write the chemical formula for the following ionic compounds:
- barium carbonate
- potassium chlorite
- iron (ii) acetate
- sodium nitride
- zinc chloride
40 name the following covalent compounds:
they all contain all nonmetals so you need to use prefixes.
1= mono, 2 = di, 3= tri, 4=tetra, 5= penta, 6 = hexa, 7= hepta, 8= octa, 9= nona, 10= deca
- sio₂
- n₂o₄
- sf₆
- co

Question

36. how many protons, neutrons, and electrons are located in the following elements?
| | protons | neutrons | electrons |
| --- | --- | --- | --- |
| a. chlorine |  |  |  |
| b. neon |  |  |  |
37. find the molar mass of the following compounds- use correct units!
 a. mgco₃
 b. ni(no₃)₂
know the polyatomic ions!!!!
38. name the following ionic compounds including a metal and a nonmetal or a polyatomic ion.
 if the second element is a nonmetal, it ends with -ide
 if the second element is a polyatomic ion, it ends with the name of the polyatomic ion
 if the metal is a transition metal, the name includes the charge in roman numerals. figure out the charge
 of the transition metal by using the charge of the nonmetal or the polyatomic ion.
 - kf
 - nio
 - cuse
 - limno₄
 - agoh
39 write the chemical formula for the following ionic compounds:
 - barium carbonate
 - potassium chlorite
 - iron (ii) acetate
 - sodium nitride
 - zinc chloride
40 name the following covalent compounds:
 they all contain all nonmetals so you need to use prefixes.
 1= mono, 2 = di, 3= tri, 4=tetra, 5= penta, 6 = hexa, 7= hepta, 8= octa, 9= nona, 10= deca
 - sio₂
 - n₂o₄
 - sf₆
 - co

Accepted Answer

### Problem 36a: Chlorine (Protons, Neutrons, Electrons)
# Explanation:
## Step 1: Protons (Atomic Number)
Chlorine has atomic number $ Z = 17 $, so protons $ = 17 $.
## Step 2: Electrons (Neutral Atom)
In neutral atom, electrons = protons $ = 17 $.
## Step 3: Neutrons (Mass Number - Atomic Number)
Chlorine - 35 (most common isotope): mass number $ A = 35 $. Neutrons $ = A - Z = 35 - 17 = 18 $.

# Answer (Chlorine):
Protons: $ 17 $, Neutrons: $ 18 $ (for $ ^{35}\text{Cl} $), Electrons: $ 17 $

### Problem 36b: Neon (Protons, Neutrons, Electrons)
# Explanation:
## Step 1: Protons (Atomic Number)
Neon has atomic number $ Z = 10 $, so protons $ = 10 $.
## Step 2: Electrons (Neutral Atom)
In neutral atom, electrons = protons $ = 10 $.
## Step 3: Neutrons (Mass Number - Atomic Number)
Neon - 20 (most common isotope): mass number $ A = 20 $. Neutrons $ = 20 - 10 = 10 $.

# Answer (Neon):
Protons: $ 10 $, Neutrons: $ 10 $ (for $ ^{20}\text{Ne} $), Electrons: $ 10 $

### Problem 37a: Molar Mass of $ \text{MgCO}_3 $
# Explanation:
## Step 1: Atomic Masses
$ \text{Mg} = 24.31 \, \text{g/mol} $, $ \text{C} = 12.01 \, \text{g/mol} $, $ \text{O} = 16.00 \, \text{g/mol} $.
## Step 2: Sum Masses
$ \text{MgCO}_3 $: $ 1 \times \text{Mg} + 1 \times \text{C} + 3 \times \text{O} $
$ = 24.31 + 12.01 + (3 \times 16.00) $
$ = 24.31 + 12.01 + 48.00 = 84.32 \, \text{g/mol} $.

# Answer ($ \text{MgCO}_3 $):
Molar mass: $ 84.32 \, \text{g/mol} $

### Problem 37b: Molar Mass of $ \text{Ni(NO}_3\text{)}_2 $
# Explanation:
## Step 1: Atomic Masses
$ \text{Ni} = 58.69 \, \text{g/mol} $, $ \text{N} = 14.01 \, \text{g/mol} $, $ \text{O} = 16.00 \, \text{g/mol} $.
## Step 2: Sum Masses
$ \text{Ni(NO}_3\text{)}_2 $: $ 1 \times \text{Ni} + 2 \times (\text{N} + 3 \times \text{O}) $
$ = 58.69 + 2 \times (14.01 + 48.00) $
$ = 58.69 + 2 \times 62.01 = 58.69 + 124.02 = 182.71 \, \text{g/mol} $.

# Answer ($ \text{Ni(NO}_3\text{)}_2 $):
Molar mass: $ 182.71 \, \text{g/mol} $

### Problem 38: Naming Ionic Compounds
#### $ \text{KF} $
# Explanation:
- $ \text{K}^+ $ (potassium, group 1, charge $ +1 $) and $ \text{F}^- $ (fluoride, nonmetal, ends with -ide).
- Name: Potassium Fluoride.

#### $ \text{NiO} $
# Explanation:
- $ \text{Ni} $ (transition metal) and $ \text{O}^{2-} $ (oxide, nonmetal). Charge of $ \text{Ni} $: $ 0 = \text{Ni}^{x+} + \text{O}^{2-} \implies x = +2 $.
- Name: Nickel(II) Oxide.

#### $ \text{CuSe} $
# Explanation:
- $ \text{Cu} $ (transition metal) and $ \text{Se}^{2-} $ (selenide, nonmetal). Charge of $ \text{Cu} $: $ 0 = \text{Cu}^{x+} + \text{Se}^{2-} \implies x = +2 $.
- Name: Copper(II) Selenide.

#### $ \text{LiMnO}_4 $
# Explanation:
- $ \text{Li}^+ $ (lithium) and $ \text{MnO}_4^- $ (permanganate, polyatomic ion).
- Name: Lithium Permanganate.

#### $ \text{AgOH} $
# Explanation:
- $ \text{Ag}^+ $ (silver, group 11, charge $ +1 $) and $ \text{OH}^- $ (hydroxide, polyatomic ion).
- Name: Silver Hydroxide.

### Problem 39: Writing Chemical Formulas
#### Barium Carbonate
# Explanation:
- $ \text{Ba}^{2+} $ (barium) and $ \text{CO}_3^{2-} $ (carbonate). Charge balance: $ 1 \times \text{Ba}^{2+} + 1 \times \text{CO}_3^{2-} = 0 $.
- Formula: $ \text{BaCO}_3 $.

#### Potassium Chlorite
# Explanation:
- $ \text{K}^+ $ (potassium) and $ \text{ClO}_2^- $ (chlorite). Charge balance: $ 1 \times \text{K}^+ + 1 \times \text{ClO}_2^- = 0 $.
- Formula: $ \text{KClO}_2 $.

#### Iron(II) Acetate
# Explanation:
- $ \text{Fe}^{2+} $ (iron(II)) and $ \text{C}_2\text{H}_3\text{O}_2^- $ (acetate, $ -1 $ charge). Charge balance: $ 1 \times \text{Fe}^{2+} + 2 \times \text{C}_2\text{H}_3\text{O}_2^- = 0 $.
- Formula: $ \text{Fe(C}_2\text{H}_3\text{O}_2\text{)}_2 $.

#### Sodium Nitride
# Explanation:
- $ \text{Na}^+ $ (sodium) and $ \text{N}^{3-} $ (nitride). Charge balance: $ 3 \times \text{Na}^+ + 1 \times \text{N}^{3-} = 0 $.
- Formula: $ \text{Na}_3\text{N} $.

#### Zinc Chloride
# Explanation:
- $ \text{Zn}^{2+} $ (zinc) and $ \text{Cl}^- $ (chloride). Charge balance: $ 1 \times \text{Zn}^{2+} + 2 \times \text{Cl}^- = 0 $.
- Formula: $ \text{ZnCl}_2 $.

### Problem 40: Naming Covalent Compounds
#### $ \text{SiO}_2 $
# Explanation:
- $ \text{Si} $ (1 atom: mono-) and $ \text{O} $ (2 atoms: di-). Name: Silicon Dioxide.

#### $ \text{N}_2\text{O}_4 $
# Explanation:
- $ \text{N} $ (2 atoms: di-) and $ \text{O} $ (4 atoms: tetra-). Name: Dinitrogen Tetroxide.

#### $ \text{SF}_6 $
# Explanation:
- $ \text{S} $ (1 atom: mono-) and $ \text{F} $ (6 atoms: hexa-). Name: Sulfur Hexafluoride.

#### $ \text{CO} $
# Explanation:
- $ \text{C} $ (1 atom: mono-) and $ \text{O} $ (1 atom: mono-). Name: Carbon Monoxide.

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Problem 36a: Chlorine (Protons, Neutrons, Electrons)

Step 1: Protons (Atomic Number)

Step 2: Electrons (Neutral Atom)

Step 3: Neutrons (Mass Number - Atomic Number)

Step 1: Protons (Atomic Number)

Step 2: Electrons (Neutral Atom)

Step 3: Neutrons (Mass Number - Atomic Number)

Step 1: Atomic Masses

Step 2: Sum Masses

Answer:

Problem 36b: Neon (Protons, Neutrons, Electrons)