QUESTION IMAGE
Question
for #34 – 35 use the diagram at right.
- find the value of w and identify the theorem or postulate used.
a. 36°, base angle thm.
b. 72°, base angle thm.
c. 144°, triangle sum thm.
d. 108°, linear pair post.
(diagram: an isosceles triangle with two sides labeled 10, vertex angle 36°, and a segment from the base vertex to the extended base forming angles w and h)
Step1: Identify Triangle Type
The triangle has two sides of length 10, so it's isosceles. By the Base Angle Theorem, the base angles are equal. One base angle is \(36^\circ\), so the other base angle (angle \(w\)) is also \(36^\circ\)? Wait, no—wait, the angle at the top is \(36^\circ\), and the two equal sides are the legs? Wait, no, the diagram shows a triangle with two sides 10, so the base angles (opposite the equal sides) are equal. Wait, actually, the angle at the vertex is \(36^\circ\), and the two equal sides are the sides adjacent to the \(36^\circ\) angle? Wait, no, let's re-examine. The triangle has two sides of length 10, so it's isosceles with those two sides as the equal sides. Therefore, the base angles (the angles opposite the equal sides) are equal? Wait, no, the equal sides are the legs, so the base angles (the angles at the base) are equal. Wait, the angle given is \(36^\circ\) at the vertex. Then, using the Triangle Sum Theorem, the sum of angles in a triangle is \(180^\circ\). So the two base angles (let's call them \(w\)): \(36^\circ + w + w = 180^\circ\)? Wait, no, maybe I got the angle wrong. Wait, the diagram: there's a triangle with two sides 10, and an angle of \(36^\circ\) at the left vertex. Then, the other two angles: one is \(w\) (the angle at the base, adjacent to the extended side), and the other is... Wait, no, the triangle is isosceles with two sides 10, so the base angles (the angles opposite the equal sides) are equal. Wait, the equal sides are the two sides of length 10, so the angles opposite them are equal. Wait, the angle at the left is \(36^\circ\), so the other two angles: let's call them \(x\) and \(x\). Then \(36 + 2x = 180\), so \(2x = 144\), \(x = 72\). Wait, but then the angle \(w\) is adjacent to the extended side, forming a linear pair. So linear pair postulate: \(w + x = 180\)? Wait, no, maybe the angle \(w\) is the base angle? Wait, the options: A. 36, Base Angle Thm; B. 72, Base Angle Thm; C. 144, Triangle Sum Thm; D. 108, Linear Pair Post. Wait, let's re-express.
Wait, the triangle is isosceles with two sides 10, so the base angles (the angles opposite the equal sides) are equal. The vertex angle is \(36^\circ\), so the base angles (each) are \(\frac{180 - 36}{2} = 72^\circ\). But then, the angle \(w\) is adjacent to one of the base angles, forming a linear pair? Wait, no, the diagram shows a triangle with a side extended, forming an angle \(h\) and \(w\). Wait, maybe the angle \(w\) is the vertex angle? No, the options: A says 36, Base Angle Thm. Wait, Base Angle Theorem states that in an isosceles triangle, the angles opposite the equal sides are equal. So if the two sides are 10, the angles opposite them are equal. So if one angle is 36, the other is 36? But then the third angle would be 180 - 36 - 36 = 108. But that doesn't match. Wait, maybe the angle given is a base angle. So if the base angles are 36, then the vertex angle is 180 - 36 - 36 = 108. Then, the angle \(w\) is the vertex angle? No, the options: A. 36, Base Angle Thm; B. 72, Base Angle Thm; C. 144, Triangle Sum Thm; D. 108, Linear Pair Post.
Wait, let's look at the diagram again. The triangle has two sides of length 10, so it's isosceles. The angle at the left is 36 degrees. Then, the other two angles: one is \(w\) (at the base, adjacent to the extended side), and the other is... Wait, maybe the angle \(w\) is equal to 36 degrees by the Base Angle Theorem? Wait, Base Angle Theorem: if two sides are equal, the angles opposite are equal. So if the two sides of length 10 are the legs, then the angles opposite th…
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B. 72, Base Angle Thm.