Question

30
10 yd
13 yd
7 yd
19 yd
area =
5)

Explanation:

Step1: Calculate the area of the upper trapezoid

The formula for the area of a trapezoid is \(A=\frac{(a + b)h}{2}\), where \(a = 10\) yd, \(b\) is the length of the middle - line (we can assume the middle - line of the upper trapezoid and lower trapezoid is related to the overall figure). Here, for the upper trapezoid, \(a = 10\) yd, \(b\) (the non - parallel side related to the lower part, but we can also split the figure into two trapezoids. Let's assume the height of the upper trapezoid \(h_1\) and the lower trapezoid \(h_2\), and \(h_1+h_2 = 13\) yd. Another way: we can consider the figure as composed of two trapezoids. The formula for the area of the whole figure (using the formula for the sum of two trapezoids which is equivalent to \(A=\frac{(a + c)H}{2}\), where \(a = 10\) yd, \(c=19\) yd, \(H = 13\) yd.

$$A=\frac{(10 + 19)\times13}{2}$$

Step2: Simplify the expression

First, calculate the sum inside the parentheses: \(10+19=29\). Then multiply by \(13\): \(29\times13 = 377\). Then divide by \(2\): \(\frac{377}{2}=188.5\)

Answer:

\(188.5\) square yards