Question

2x+12=3x-31; 3; 4x-12=12-4x; 12; 5+3x=5x-19

Explanation:

Step1: Solve \(2x + 12 = 3x - 31\)

Subtract \(2x\) from both sides: \(12 = x - 31\)
Add 31 to both sides: \(x = 12 + 31 = 43\)

Step2: Solve \(4x - 12 = 12 - 4x\)

Add \(4x\) to both sides: \(8x - 12 = 12\)
Add 12 to both sides: \(8x = 24\)
Divide by 8: \(x = \frac{24}{8} = 3\)

Step3: Solve \(5 + 3x = 5x - 19\)

Subtract \(3x\) from both sides: \(5 = 2x - 19\)
Add 19 to both sides: \(24 = 2x\)
Divide by 2: \(x = \frac{24}{2} = 12\)

Answer:

For \(2x + 12 = 3x - 31\), \(x = 43\); for \(4x - 12 = 12 - 4x\), \(x = 3\); for \(5 + 3x = 5x - 19\), \(x = 12\)