Question

1. (8, 2);

x - y = 6
2x - 10y = 4

Explanation:

We need to check if the point \((8, 2)\) is a solution to the system of equations \(

$$\begin{cases}x - y = 6\\2x - 10y = 4\end{cases}$$

\)

Step 1: Check the first equation

Substitute \(x = 8\) and \(y = 2\) into the first equation \(x - y = 6\)
Left side: \(x - y = 8 - 2 = 6\)
Right side: \(6\)
Since \(6 = 6\), the point satisfies the first equation.

Step 2: Check the second equation

Substitute \(x = 8\) and \(y = 2\) into the second equation \(2x - 10y = 4\)
Left side: \(2x - 10y = 2\times8 - 10\times2 = 16 - 20 = -4\)
Right side: \(4\)
Since \(-4
eq4\), the point does not satisfy the second equation.

Answer:

The point \((8, 2)\) is not a solution to the system of equations because it satisfies the first equation \(x - y = 6\) (as \(8 - 2 = 6\)) but does not satisfy the second equation \(2x - 10y = 4\) (as \(2\times8 - 10\times2 = - 4
eq4\)).