Question

c + 2f₂ → cf₄
how many grams of carbon tetrafluoride, cf₄, are produced from the complete reaction of 4.0 moles of fluorine, f₂?
molar mass cf₄: 88.01 g/mol
? g cf₄

Explanation:

Step1: Determine the mole ratio

From the balanced equation \(C + 2F_{2}\to CF_{4}\), the mole ratio of \(F_{2}\) to \(CF_{4}\) is \(2:1\).

Step2: Calculate moles of \(CF_{4}\)

Given \(n(F_{2}) = 4.0\space mol\). Using the mole ratio \(\frac{n(CF_{4})}{n(F_{2})}=\frac{1}{2}\), then \(n(CF_{4})=\frac{1}{2}\times n(F_{2})\). Substituting the value of \(n(F_{2})\), we get \(n(CF_{4})=\frac{1}{2}\times4.0\space mol = 2.0\space mol\).

Step3: Calculate mass of \(CF_{4}\)

Using the formula \(m = n\times M\), where \(M(CF_{4})=88.01\space g/mol\) and \(n(CF_{4}) = 2.0\space mol\). Then \(m(CF_{4})=n(CF_{4})\times M(CF_{4})=2.0\space mol\times88.01\space g/mol\)
\(m(CF_{4}) = 176.02\space g\)

Answer:

\(176.02\space g\)