Question

2c₂h₂(g) + 5o₂(g) → 4co₂(g) + 2h₂o(g)
how many liters of c₂h₂ will react with 12.0 mol o₂ assuming the reaction is at stp?
? l c₂h₂

Explanation:

Step1: Find mole ratio of \( C_2H_2 \) and \( O_2 \)

From the reaction \( 2C_2H_2(g) + 5O_2(g)
ightarrow 4CO_2(g) + 2H_2O(g) \), the mole ratio of \( C_2H_2 \) to \( O_2 \) is \( \frac{2}{5} \).

Step2: Calculate moles of \( C_2H_2 \)

Let \( n_{C_2H_2} \) be moles of \( C_2H_2 \). Using the ratio:
\( \frac{n_{C_2H_2}}{12.0\ \text{mol}\ O_2} = \frac{2}{5} \)
\( n_{C_2H_2} = 12.0\ \text{mol} \times \frac{2}{5} = 4.8\ \text{mol} \)

Step3: Convert moles to liters at STP

At STP, 1 mol of gas = 22.4 L.
Volume of \( C_2H_2 = 4.8\ \text{mol} \times 22.4\ \text{L/mol} = 107.52\ \text{L} \)

Answer:

107.52