Question

\\\sqrt3{27x^4y^9}\\

Explanation:

⚡ Using what you learned: simplifying radical expressions

Step 1: Split the radical

$$ \sqrt[3]{27x^4y^9} = \sqrt[3]{27} \cdot \sqrt[3]{x^4} \cdot \sqrt[3]{y^9} $$

Step 2: Simplify each part

$$ \sqrt[3]{27} = 3 $$

$$ \sqrt[3]{x^4} = \sqrt[3]{x^3 \cdot x} = x\sqrt[3]{x} $$

$$ \sqrt[3]{y^9} = y^3 $$

Step 3: Combine terms

$$ 3 \cdot x\sqrt[3]{x} \cdot y^3 = 3xy^3\sqrt[3]{x} $$

Answer:

$$ 3xy^3\sqrt[3]{x} $$