QUESTION IMAGE
Question
- mg^{+2} & s^{-2}
name:________________________
- mg^{+2} & n^{-3}
name:________________________
- na^{+} & p^{-3}
name:________________________
naming ionic compounds
- what are the prefixes for naming covalent compounds?
- how do you determine which type of chemical bond atoms of a compound have?
mixed naming compounds
directions: classify each compound as ionic or covalent, and then write the compound name.
- mgo □ ionic □ covalent
________________________
- sf_{6} □ ionic □ covalent
________________________
- na_{2}o □ ionic □ covalent
________________________
- cacl_{2} □ ionic □ covalent
________________________
- no □ ionic □ covalent
________________________
- p_{4}o_{10} □ ionic □ covalent
________________________
- as_{2}o_{5} □ ionic □ covalent
________________________
writing chemical formulas
directions: write the chemical formula based on the compound name given.
- copper sulfide ________________
- xenon hexafluoride ________________
- phosphorus pentoxide ________________
- dinitrogen tetroxide ________________
- sulfur difluoride ________________
- dinitrogen pentoxide ________________
- selenium hexachloride ________________
- dicarbon tetrahydride ________________
Question 25: $Mg^{+2}$ & $S^{-2}$
Step1: Determine the formula
To form a neutral compound, the charges must balance. The charge of $Mg$ is $+2$ and $S$ is $-2$. The ratio of $Mg$ to $S$ is $1:1$ (since $2$ and $2$ cancel out). So the formula is $MgS$.
Step2: Name the ionic compound
For ionic compounds, we use the name of the cation (magnesium) and the anion (sulfide, since sulfur gains 2 electrons, so the suffix is -ide).
Step1: Determine the formula
The charge of $Mg$ is $+2$ and $N$ is $-3$. To balance charges, we find the least common multiple of 2 and 3, which is 6. So we need 3 $Mg$ ions ($3 \times +2 = +6$) and 2 $N$ ions ($2 \times -3 = -6$). The formula is $Mg_3N_2$.
Step2: Name the ionic compound
Cation: magnesium, anion: nitride (nitrogen gains 3 electrons, suffix -ide).
Step1: Determine the formula
Charge of $Na$ is $+1$, charge of $P$ is $-3$. To balance, we need 3 $Na$ ions ($3 \times +1 = +3$) and 1 $P$ ion ($1 \times -3 = -3$). Formula: $Na_3P$.
Step2: Name the ionic compound
Cation: sodium, anion: phosphide (phosphorus gains 3 electrons, suffix -ide).
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
Magnesium sulfide