Question

1. the moon does not orbit earth in a circular path as the distance between these two objects changes. during a micromoon, the moon is at its farthest point to earth (406,555,000 m). determine the effects of earths gravitational field on the moon at this point, known as the apogee. earths mass is 6×10²⁴ kg.

2.42 n/kg
2.42×10⁵ n/kg
2.42×10⁻⁵ n/kg
2.42×10⁻⁴ n/kg

Explanation:

Step1: Recall the formula for gravitational field strength

The formula for gravitational field strength \(g\) is \(g = \frac{GM}{r^{2}}\), where \(G = 6.67\times 10^{-11}\ \text{N}\cdot\text{m}^{2}/\text{kg}^{2}\) (the gravitational constant), \(M\) is the mass of the Earth, and \(r\) is the distance from the Earth to the Moon.

Step2: Substitute the given values into the formula

Given \(M = 6\times 10^{24}\ \text{kg}\) and \(r=406555000\ \text{m}\)

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Answer:

D. \(2.42\times10^{-4}\ \text{N/kg}\)