Question

1. \\(\frac{1}{6}(p + 24) = 10\\)

\\(left(\frac{1}{6} \cdot \boxed{} \
ight) + \left(\frac{1}{6} \cdot \boxed{} \
ight) = \boxed{}\
p = \boxed{}\\)

Explanation:

Step1: Apply distributive property

$\frac{1}{6}(p+24) = \frac{1}{6} \cdot 24 + \frac{1}{6} \cdot p = 10$

Step2: Simplify the constant term

$\frac{24}{6} = 4$, so $4 + \frac{p}{6} = 10$

Step3: Isolate the variable term

$\frac{p}{6} = 10 - 4$
$\frac{p}{6} = 6$

Step4: Solve for $p$

$p = 6 \times 6$

Answer:

$p = 36$
Filled blanks (from top to bottom): 24, $p$, 10, 36