Question

23 which of these equations is equivalent to $6\frac{3}{4} \times 3\frac{1}{4} = 19$? \
\circled{a} $3\frac{1}{4} \div 19 = 6\frac{3}{4}$ \
\circled{b} $19 \div 3\frac{1}{4} = 6\frac{3}{4}$ \
\circled{c} $3\frac{1}{4} \div 6\frac{3}{4} = 19$ \
\circled{d} $6\frac{3}{4} \div 3\frac{1}{4} = 19$

Explanation:

Step1: Recall multiplication equivalence rule

For \(a \times b = c\), equivalent division: \(c \div b = a\)

Step2: Assign values to variables

Let \(a = 6\frac{3}{4}\), \(b = 3\frac{1}{4}\), \(c = 19\). So \(19 \div 3\frac{1}{4} = 6\frac{3}{4}\)

Step3: Match with options

The equation matches option B.

Answer:

B. \(19 \div 3\frac{1}{4} = 6\frac{3}{4}\)